Find the midpoint of the sides of a triangle w/ vertices

Question

A (-3,-4) B (6,-2) and C (3,8)?

Answer 1

The vertices are A(-3, -4), B(6, -2) and C(3, 8)

Calculate the mid point of sides by using formula [(x₁ + x₂)/2, (y₁ + y₂)/2]

A(-3, -4) = (x₁, y₁), B(6, -2) = (x₂, y₂)

AB side mid point is = [(- 3 + 6)/2, (- 4 - 2)/2]

= [ (3/2), -3]

B(6, -2) = (x₁, y₁), C(3, 8) = (x₂, y₂)

BC side mid point is = [(6 + 3)/2, (- 2 + 8)/2]

= [(9/2), 3]

C(3, 8) = (x₁, y₁), A(-3, -4) = (x₂, y₂)

BC side mid point is = [(3 - 3)/2, (8 - 4)/2]

= [0, 2]

Mid points are [(3/2), - 3],[(9/2), 3] and (0,2).