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x^4-x^2-6=0
asked Sep 20, 2014 in ALGEBRA 2 by anonymous

1 Answer

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The equation x4 - x2 - 6 = 0

(x2)2 - x2 - 6 = 0

Let x2 = X

Now the equation becomes X2 - X - 6 = 0

  • Factorize the above equation

X2 - 3X + 2X - 6 = 0

X(X - 3) + 2(X - 3) = 0

(X - 3) (X + 2) = 0

Apply zero product property.

X - 3 = 0 and X + 2 = 0

X = 3 and X = - 2

Back substitute X = x2

x2 = 3 and x2 = - 2

  • Now solve x2 = 3

Apply squre root on each side.

x = √3

x = ± 1.732

  • And solve x2 = - 2

Apply squre root on each side.

x = √(- 2)

x = √(i2 )(2)

x = ± 1.414 i

Solutions of the equation x4 - x2 - 6 = 0 are at x = ± 1.732 and x = ± 1.414 i.

answered Sep 20, 2014 by david Expert
edited Sep 20, 2014 by david

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