Question

What is the result of isolating y^2 in the equation below?

(x+6)^2 + y^2 = 1

 

A.) y^2 = -x^2 - 12x -35 
B.) y^2 = x^2 + 12x + 37
C.) y^2 = -x^2 - 35
D.) y^2 = x^2 + 37

Answer 1

The equation is (x + 6)² + y² = 1 and solve for y².

Subtract (x + 6)² from each side.

(x + 6)² + y² - (x + 6)² = 1 - (x + 6)²

y² = 1 - (x + 6)²

Apply Square of a Binomial : (u + v)² = u² + 2uv + v².

y² = 1 - [x² + 2(x)(6) + 6²]

y² = 1 - (x² + 12x + 36)

y² = - x² -12x - 35.

The option A is correct.