How much of each should be used?

Question

E Chem Testing has a solution that is 80% base and another 30% base. A technician needs 150 L of a solution that is 62% base. The 150 L will be prepared by mixing the two solutions by hand. How much of each should be used?

Answer 1

Let the quantity of a base-1 which has 80% of base is x .

Quantity of total solution is 150 L

So the quantity of a base-2 which has 30% of base is 150-x .

The mixed solution of 150 L has a 62% of base .

So mathematically 150*62 = x*80 + (150 - x)*30

150*62 = x*80 + (150 - x)*30

80x + 150*30 - 30x = 150*62

50x + 150*30= 150*62

50x = 150*62 - 150*30

50x =150(62-30)

50x = 150*32

x = (150*32) / 50

x = 3*32

x = 96

So the quantity of a base-1 which has 80% of base is 96 L .

The quantity of a base-2 which has 30% of base is 150-96 =46 L .