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Two whole numbers differ by 3. The sum of their square is 89 what are the numbers?
asked Nov 5, 2014 in PRECALCULUS by anonymous

1 Answer

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Two whole numbers differ by 3 .

Let the first whole number is x .

So second whole number is x+3  .

The sum of their square is 89 .

x² +(x+3)² = 89

x² +x² + 9 +6x = 89

2x² +6x -80 = 0 

x² +3x -40 = 0

x² +8x -5x -40 = 0

x(x +8) -5(x+8) = 0

(x +8)(x-5) = 0

x = -8 and x = 5

x = -8 not valid    [ it is not a whole number]

So the first whole number is x = 5 .

The second whole number is x + 3 = 8

answered Nov 5, 2014 by friend Mentor

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