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How to factor

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12xy-4xz-48y^2+16yz?

asked Dec 8, 2014 in PRECALCULUS by anonymous
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1 Answer

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The polynomial is 12xy - 4xz - 48y² + 16yz.

Common out 4 from the polynomial.

12xy - 4xz - 48y² + 16yz = 4(3xy - xz - 12y² + 4yz)

By factoring by grouping.

= 4[x(3y - z) - 4y(3y - z)]

= 4(3y - z)(x - 4y).

The factor of 12xy - 4xz - 48y² + 16yz is 4(3y - z)(x - 4y).

answered Dec 8, 2014 by lilly Expert

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