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I need to factor the polynomial 18a^2b^3c-45ab^6c completely

0 votes

factoring polynomials

asked Dec 2, 2013 in ALGEBRA 1 by harvy0496 Apprentice
reshown Dec 2, 2013 by goushi

1 Answer

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Given binomial is 18a^2b^3c-45ab^6c

= (9*2*a*a*b*b*b*c)-(9*5*a*b*b*b*b*b*b*c)

Take common out possible terms from above expression.

= (9ab^3c)(2a-5b^3)

Factoring of given binomial is (9ab^3c)(2a-5b^3).

answered Dec 30, 2013 by dozey Mentor

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