slope-intercept form

Question

How to solve this problem?

line perpendicular to 2x-3y+1=0 and has a y intercept of 2/3

 

Please help!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Given equation is 2x-3y+1=0

Write the equation in slope intercept form

y= 2/3x+1/3

Compare the above equation with slope intercept form y=mx+b, where m is slope and b is intercept.

Here slope m=2/3

If two lines are perpendicular, the slope (m₁) of one line is opposite reciprocal of the second line slope (m₂). It can be represented as, .

slope of new line m= -3/2

Given y intercept is 2/3.

Substitute slope and intercept in y=mx+b

y=-3/2x+2/3

The perpendicular line to2x-3y+1=0 is y=-3/2x+2/3.