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line that passes through the point (3 , -11) and is parallel to the line y=-3x+4

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Find the equation of the line that passes through the point (3 , -11) and is parallel to the line

equation-of-a-line

asked Dec 3, 2013 in ALGEBRA 1 by rockstar Apprentice

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1 Answer

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Given line y = -3x+4

Slope say m1 = -3

Parallel lines have equal slope.

So slope of required line say m2 = -3.

Point(x1,y1) = (3,-11)

Line equation is y+11 = -3(x-3)

y+11 = -3x+9

Subtract 11 from each side.

y+11-11 = -3x+9-11

y = -3x-2

Required line equation is y = -3x-2.

answered Dec 3, 2013 by william Mentor

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