whats the equation of a line that is parallel to y = -1/2 x + 3 and passes through the point (8,-4)?

Question

Equation of a line that is parallel to y = - 1/2 x+ 3 and passes through the point (8,-4)

Answer 1

Given line y = -1/2x+3

Slope of the given line say m1 = -1/2

We know that parallel lines have equal slope.

parallel line slope say m2 = -1/2 and the point (x1,y1) = (8,-4)

Required line equation is y+4 = -1/2(x-8)

2(y+4) = -x+8

2y+8 = -x+8

Subtract 8 from each side.

2y+8-8 = -x+8-8

2y = -x

Divide to each side by 2.

2y/2 = -x/2

y = (-1/2)x

Required line equation is y = (-1/2)x