how do i find the slope of the line parallel to the graph of 3x-4y=12?

Question

i have tried to understand this countless times but i still dont get it

Answer 1

Given line 3x-4y = 12

Standard form of line y = mx+c

Subtract 3x from each side.

3x-4y-3x = 12-3x

-4y = 12-3x

Divide to each side by negitive one.

-4y/-4 = 12/-4-3x/-4

y = -3+3/4x

Slope of given line m1 = 3/4

From the graph we can observe  the line 3x-4y = 2

Slope  = rise/run = change in y/change in x

 m = 3/4

Parallal line have equal slope,so the slope of the line parallal to 3x-4y is 3/4.