How would you graph 3x+y=21

Question

I need to know what it would look like if you graphed 3x+y=21.

Answer 1

The line equation is 3x + y = 21.

Write the equation in slope - intercept form y = mx + b, where m is slope and b is y-intercept.

y = - 3x + 21.

Compare the equation with slope - intercept form y = mx + b.

slope = - 3 and y - intercept is 21.

y - intercept is 21, so the line crosses the y - axis at (0, 21).

Using slope find the next point.

Slope = rise/run = - 3/1

Start at point (0, 21), move 3 units down and 1 unit right, then plot the point (1, 18).

Draw a line through these points.

Graph :