how do I graph 2x+4y=-8

Question

I need to graph this can cannot for the life of me remember how.

Answer 1

Write the equation in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

The equation is 2x + 4y = -8.

Divide each side by 2.

x + 2y = - 4.

Subtract x from each side.

2y = - 4 - x

Divide each side by 2.

y = - 4/2 - x/2

y = - 2 - x/2 = - x/2-2.

Compare the equation with slope-intercept form y = mx + b.

slope = -1/2 and y-intercept is -2.

y-intercept is -2, so the line crosses the y-axis at (0, -2)

Using slope find the next point.

Slope = rise/run = -1/2

Start at point (0, -2), move 1 unit down and 2 units right, then plot the point (2, -3).

Draw a line through these points.

Graph :

 

Comments

Everything is correct, but you label the equation in graph is y = - x + 3

The correct equation is y = - x/2 - 2.