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y = 8 when x = -32, what is y when x = 64?

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the value of y varies directly with x.
asked Mar 8, 2014 in ALGEBRA 2 by skylar Apprentice

1 Answer

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Direct variation is y = kx

The given numbers form one ratio expressd as y/x = 8/-32

To find when x = 64

We set up another ratio y/64

By the definition both ratios are equal 8/-32 = y/64

Multiple each side by 64.

(8/-32)64 = (y/64)64

-8*2 =y

y = -16.

answered Mar 8, 2014 by david Expert

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