graph y=34+15x and Y=20+35x

Question

Where do these intercept y=34+15x and y=20+35x.

Answer 1

Write the equations in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

The first equation is  y = 34 +15x    →(1)

Group like terms.

y = 15x + 34.

Compare the equation with slope-intercept form y = mx + b.

slope = 15 and y-intercept is 34.

y-intercept is 34, so the line crosses the y-axis at (0, 34)

Using slope find the next point.

Slope = rise/run = 15/1

Start at point (0, 34), move 15 units up and 1 unit right, then plot the point (1, 49).

The second equation is y = 20 + 35x  →(2)

Group like terms.

y = 35x + 20.

Compare the equation with slope-intercept form y = mx + b.

slope = 35 and y-intercept is  20.

y-intercept is 20, so the line crosses the y-axis at (0, 20)

Using slope find the next point.

Slope = rise/run = 35/1

Start at point (0, 20), move 35 units up and 1 unit right, then plot the point (55, 1).

Draw two lines through these points.

Graph :

From the graph the intersection point is (0.7, 44.5).

So,the solution of the system ix x = 0.7 and y = 44.5.