draw the graph of linear equation 5x-2y-10=0

Question

from the graph ,find the value of abscissa when the value of ordinate is 5

 

Answer 1

The equation is 5x - 2y - 10 = 0

Write the equation in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

5x - 2y - 10 = 0

y =  5x/2 - 5

Compare the equation with slope-intercept form y = mx + b.

slope = 5/2 and y - intercept is - 5.

y-intercept is - 5, so the line crosses the y - axis at (0, - 5)

Using slope find the next point.

Slope = rise/run = 5/2

Start at point (0, - 5), move 5 units up and 2 units right, then plot the point (0, 2).

Draw a line through these points.

Graph :

From the graph the value of abscissa is 4 when the value of ordinate is 5.