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Graph the lines containing these points and find their slope.

0 votes
(2,5) and (-3,10).
asked Mar 14, 2014 in ALGEBRA 1 by futai Scholar

1 Answer

0 votes

The points are (2, 5) and (- 3, 10).

Slope - intercept form : y = mx + b.

Line equation formula : y - y₁ = (y₂ - y₁)/(x₂ - x₁)(x - x₁).

Substitute the values of (x₁, y₁) = (2, 5) and (x, y) = (- 3, 10) in Line equation formula.

y - 5 = [(10 - 5)/(- 3 - 2)](x - 2)

y =[5/- 5](x - 2) + 5

y = - x + 7.

Compare the equation with slope-intercept form y = mx + b.

slope = - 1 and y-intercept is 7.

y-intercept is 7, so the line crosses the y-axis at (0, 7)

Using slope find the next point.

Slope = rise/run = -1/1

Start at point (0, 7), move 1 unit down and 1 unit right, then plot the point (1, 6).

Draw a line through these points.

Graph :

graph for the equation - x - 2y = 8

answered Mar 15, 2014 by dozey Mentor

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