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sole for x

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sqrt(2x^2+5)=2
asked Apr 5, 2014 in ALGEBRA 1 by rockstar Apprentice

1 Answer

0 votes

sqrt(2x^2+5)=2

Squaring on both sides

(2x^2+5)=4

2x^2=-1

Solutions are imaginary numbers.

Therefore no solution

answered Apr 5, 2014 by bradely Mentor

The equation is √(2x2 + 5) = 4.

Squaring on bboth sides we get,

2x2 + 5 = 4

2x2 = 4 - 5

2x2 = -1

x2 = -1/2

x = √(-1/2)

x = ± i / √2

x = ± 0.70711i

The solution is x = ± 0.70711i.

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