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Write a quadratic equation whose roots are

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6+-2sqrt5.?

asked Oct 21, 2014 in ALGEBRA 2 by anonymous

1 Answer

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The roots of quadratic equation are 6 + 2√ 5 and 6 - 2√ 5

From factor theorem, when f(c) = 0 then x - c is a factor of polynomial.

f(x) = [x - (6 + 2√5)][x - (6 - 2√5)]

= [ x - 6 - 2√5][x - 6 + 2√5]

= [(x - 6) - 2√5][(x - 6) + 2√5]

= [(x - 6)2 - (2√5)2]

= x2 + 36 - 12x - 20

f(x) = x2 - 12x + 16

Required quadratic equation is x2 - 12x + 16.

answered Oct 21, 2014 by david Expert

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