Question

write a quadratic equation in standard form whose solutions are -6 and 5

Answer 1

Qudratic equation standard form is ax^2+bx+c = 0

Given -6,5 are roots of required quadratic equation.

Then (x+6)(x-5) is must be equal to 0.

(x+6)(x-5) = 0

x^2-5x+6x-30 = 0

x^2+x-30 = 0

Required quadratic equation is x^2+x-30 = 0.