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Vertex form to standard

0 votes

y-5=-2(x+1)^2

standard-form-of-an-equation

asked Oct 25, 2014 in PRECALCULUS by anonymous

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1 Answer

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Given equation : y - 5 = -2(x+1)²

Apply Square of a Binomial: (u + v)² = u² + 2uv + v².

y - 5 = -2(x²+1²+2(x)(1))

y - 5 = -2(x²+1+2x)

y - 5 = -2x² - 2 - 4x

Add 5 to each side.
y = -2x² - 2 - 4x + 5

y = -2x² - 4x + 3

The standard form of vertex form of quadratic function is y = -2x² - 4x + 3

answered Oct 25, 2014 by lilly Expert

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