abcd is a rectangle. find the length of each diagonal.

Question

AC= 3y/5 and BD= 3y-4

Answer 1

Given that ABCD is a rectangle and AC = 3y/5 and BD = 3y - 4

Given AC and BD are diagonals. In a rectangle diagonals are equal.

Therefore AC = BD

             => 3y/5 = 3y - 4

             => 3y = 5(3y - 4)

             => 3y = 15y - 20

             => 12y = 20

             => y = 20/12 = 5/3

Therefore AC = 3y/5

                         = 3(5/3)/5

                         = 1

          and BD = 3y - 4

                        = 3(5/3) - 4

                        = 5 - 4

                        = 1

Therefore length of each diagonal is 1.