Math HW help? Please Explain how its done?

Question

Suppose the area of a square is x^2-10x+25. What is the perimeter of the square?

Answer 1

Area of the square is x² -10x + 25. So, the factors of the equation will be the dimensions of the rectangle.

x² -10x + 25 = 0

x² -5x -5x + 25 = 0

x (x -5 ) -5 (x-5) = 0

(x - 5) (x-5) = 0

x = 5

Side length of the square is x = 5

Perimeter of the square = 4s. where s is the side length of the sqaure.

Perimeter of the square = 4 * 5 = 20 units.

Comments

Area(A) = (x - 5)^2 square units.

Means that, side of the square is (x - 5)

Perimeter(P) = 4a, where a is length of the side of square.

P = 4 * (x - 5) = 4x - 20 units.

Therefore, perimeter of the square is (4x - 20)units.