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Solve this restriction with absolute value:

0 votes

|2x + 1| < 3?

inequalities
absolute-values

asked Nov 12, 2013 in ALGEBRA 1 by anonymous Apprentice

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1 Answer

0 votes

|2x+1|<3

2x+1<3 or -(2x+1)<3

2x+1<3

Subtract 1 from eachside

2x+1-1<3-1

2x<2

x<1

----------------------------------

-(2x+1)<3

2x+1>-3

Subtract 1 from eachside

2x+1-1>-3-1

2x>-4

x>-2

x>-2 or x<1

-2<x<1

answered Nov 12, 2013 by bradely Mentor

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