what is the axis of symmetry of the graph of f(x)=-3x^2+3

Question

quadratic function, axis of symmetry, vertex of a parabola, f(x)=-3x^2+3 , algebra problem

Answer 1

Given f(x) = -3x^2+3

Compare it standard parabola is y = ax^2+bx+c

a = -3, b = 0, c = 3

Axis of symmetry is x = -b/2a =-0/2*-3

Axis of symmetry is x = 0

Substitute x = 0 in given equation.

y = -3x^2+3

y = 3

Vertex of parabola is (0,3)

Graph of parabola

Draw the coordinate plane.

Plot the points.

Connect the points neatly like curve.

Then there is formed required parabola.