equasion for the axix of symmetry for y=x^2+3x-7

Question

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Answer 1

Standard equation of parabola is y = ax^2+bx+c

Compare the given equation y = x^2+3x-7 to above equation.

a = 1, b = 3, c = -7

Axis of symmetry is x = -b/2a

x = -3/2(1)

→ x = -3/2

Vertex of parabola

Substitute the x value in equation y = x^2+3x-7

y = (-3/2)^2+3(-3/2)-7

y = 9/4-9/2-7

Least common multiple of 1,2,4 is 4.

y = (9-18-28)/4

y = -37/4

→ Vertex of parabola is (-3/2,-37/4).