What is the turning point and the axis of symmetry for the graph of

Question

y=(x+2)^2?

Answer 1

Given equation : y = ( x + 2 )²

We can pre-assume values of x for given equation.

Table for corresponding values of x and y.

x	( x + 2 )²	y = ( x + 2 )²
-5	( -5 + 2 )²	9
-4	( -4 + 2 )²	4
-3	( -3 + 2 )²	1
-2	( -2+ 2 )²	0
-1	( -1+ 2 )²	1
0	( 0+ 2 )²	4
1	( 1 + 2 )²	9

The graph for above table is

From above graph

Turning point is ( -2 , 0 ).

Axis of symmetry is determined using formula : x = -b/2a

y = ( x + 2 )²

y = x²+ 2² + 4x

y = x² + 4x + 4

By comparing with equation y = ax² + bx + c

a = 1 , b = 4

x = -b/2a

x = -4/2*1

x = -2

Solution :

Turning point is ( -2 , 0 ).

Axis of symmetry is x = -2