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what is the answer to, Find the slope of the line perpendincular to 2x-5y=-10?

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how do you fine perpendicular lines ?

asked Feb 20, 2014 in ALGEBRA 1 by dkinz Apprentice

1 Answer

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Given line equation 2x-5y = -10

Subtract 2x from each side.

-5y = -2x-10

Divide to each side by negitive 5.

-5y/-5 = (-2x/-5) -(10/-5)

y = 2x/5+2

Compare it to slope intercept form y = mx+b.

Slopeof the given line is 2/5.

We know that perpendicular lines slopes are negitive reciprocal to each other.

So perpendicular line slope is -5/2.

answered Feb 25, 2014 by dozey Mentor

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