solve and check 8y^2- 22y+15= 0

Question

8y^2- 22y+15= 0.

Answer 1

Given 8y^2-22y +15 = 0

8y^2-12y -10y +15 = 0

4y (2y -3)-5(2y -3) = 0

Take common out 2y -3.

(2y -3)(4y -5) = 0

To solve 2y -3 = 0 and 4y -5 = 0

2y -3 = 0

Add 3 to each side.

2y = 3

Divide to each side by 2.

y = 3/2

And 4y -5 = 0

Add 5 to each side.

4y = 5

Divide to eachside by 4.

y = 5/4

Solution y = 3/2 and 5/4.

Check :

8y^2-22y+15 = 0

For y = 3/2

8(9/4)-22(3/2)+15 = 0

18-33+15 = 0

0 = 0

For y = 5/4

8(25/16)-22(5/4)+15 = 0

(25/2)-(110/4)+15 = 0

(50-110+60)/4 = 0

0 = 0