(-6,1) , (2,5)

Question

how do i sove this problem in equation in slope-intercept form.

Answer 1

Say the points

(x1, y1) = (-6, 1)

(x2, y2) = (2, 5)

The line is y - y1 = [(y2 - y1)/(x2 -x1)](x - x1).

y - (1) = [(5 - 1)/(2 - (-6))]/(x - (-6))

y - 1 = [4/8]x + 6

y - 1 = (1/2)x + 6

y = (1/2)x + 6 + 1

y = (1/2)x + 7.

The slope intercept form of the line is y = (1/2)x + 7.

Comments

please check your answer.

Let the points are (x1, y1) = (-6, 1) and (x2, y2) = (2, 5).

Two - points form of line equation : y - y1 = [(y2 - y1)/(x2 -x1)](x - x1).

y - 1 = [(5 - 1)/(2 - (-6))](x - (-6))

y - 1 = [4/8](x + 6)

y - 1 = 1/2 (x + 6)

y - 1 = x/2 + 3

y = x/2 + 4.

The slope - intercept form of line equation is y = x/2 + 4.

Answer 2

Slope-intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

Let the points are (x1, y1) = (-6, 1) and (x2, y2) = (2, 5).

Slope m = [(y2 - y1)/(x2 -x1)]

m = [(5 - 1)/(2 - (-6))]

m  = [4/8] = 1/2

Now, the line equation is y = 1/2x + b.

Find the y-intercept by substituting any point in the line equation say (2, 5)

5 = 1/2 * 2 + b

b = 5 -1 = 4

The line equation in slope intercept form is y = 1/2x + 4