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Perpendicular Questions

0 votes
For x + 5y - 2z = 6, which of these is perpendicular to it?

a) (1,5,-2)

b) (x,5y,-2z)

c) (-3,1,1)

d) (1,1,0)

I thought it was c) but that is wrong but i thought the dot product had to be zero??

(1 x -3) + (5x1) + (-2x1) = -3 + 5 -2 = 0?

Could someone please tell me what i am doing wrong, thank you :)
asked Sep 11, 2014 in CALCULUS by zoe Apprentice
Just kidding, think i figured it out, dot product has to = 6 which it does for d)

3 Answers

0 votes

image

The option C is correct.

answered Sep 11, 2014 by casacop Expert
edited Sep 11, 2014 by casacop
I put C in my test and got it wrong so am very confused?
Sorry, my answer is wrong. Please check my new answer.
0 votes
The answer is a) (1, 5,  -2). (1, 5, -2) is the normal to the plane x+5y-2z=6 and the normal of the plane is perpendicular to the plane.
answered Sep 11, 2014 by anonymous
Thanks for correcting me.
0 votes

image

The option A is correct.

answered Sep 11, 2014 by casacop Expert
Thank you :)

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