how do i put y=3x/2+3/2 in standard form

Question

I guess algebra 2 is the same as college algebra but i am having problem with putting my math problems in standard form can you help

Answer 1

Given equation y = 3x/2+3/2

Subtract 3x/2,3/2 from each side.

y-3x/2-3/2 = 3x/2+3/2-3x/3-3/2

y-3x/2-3/2 = 0

(2y-3x-3)/2 = 0

Divide to each side by 2.

2(2y-3x-3)/2 = 0/2

2y-3x-3  = 0

Multiple to each side by negitive one.

-2y+3x+3 = 0

3x-2y+3 = 0

Subtract 3 from each side.

3x-2y+3-3 = 0-3

3x-2y = -3

Compare the standard form of equation ax+by = c

a = 3, b = -2, c = -3.

Answer 2

NOTE :

The standard form line equation is Ax + By = C. A shouldn't be negative, A and B shouldn't both be zero, and A, B and C should be integers.

The equation is y = (3/2)x + (3/2).

Eliminate the fractions by multiplying the equation with 2.

2y = 3x + 3

Subtract 2y from each side.

0 = 3x - 2y + 3

Subtract 3 from each side.

3x - 2y = - 3.