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if 3x+7y=13 and zx+8=3y is parallel, find the value of z

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if 3x+7y=13 and zx+8=3y is parallel, find the value of z.

 

asked Feb 18, 2014 in ALGEBRA 1 by linda Scholar

1 Answer

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Slope intercept form is y = mx+b

Given first line 3x+7y = 13

Subtract 3x from each side.

3x-3x+7y = 13-3x

7y = 13-3x

Divide to each side by 7.

y = (-3/7)x+13/7 ---> (1)

Second line equation is zx+8 = 3y

Divide to each side by 3.

y = (z/3)x+8/3 ---> (2)

(1)&(2) are parallel.So the slopes are equal.

-3/7 = z/3

Multiple to each side by 3.

(-3*3)/7 = z*3/3

-9/7 = z

Value of z = -9/7.

answered Feb 18, 2014 by friend Mentor

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