y = -2/3x + 2, (9, -3) line perpendicular

Question

Write the equation of a line perpendicular to the given line but passing through the given point.

Answer 1

Given line y = (-2/3)x+2

Slope say m1 = -2/3

Perpendicular line slope is say m2 .

We know that m1*m2 = -1

So m2 = 3/2. and the point (9,-3).

Equation is y+3 = 3/2(x-9)

y+3 = (3/2)x-27/2

Subtract 3 from each side.

y+3-3 = (3/2)x-27/2-3

Required line equation is y = (3/2)x-33/2